Since Bryan solved my last puzzle a little too quickly, this post will serve as a followup puzzle that may or may not be easier. All I know is that Bryan is ineligible this time around ;-)

Once again, the rules are simple. The solution must be a single line dcmd that produces precise output without any additional steps or post processing. For this puzzle, you're actually allowed two commands: one for your dcmd, and another for '::run'. For this puzzle, we'll be using the following test program:

#include 

int
main(int argc, char **argv)
{
        int i;

        srand(time(NULL));

        for (i = 0; i < 100; i++)
                write(rand() % 10, NULL, 0);

        return (0);
}

The puzzle itself demonstrates how conditional breakpoints can be implemented on top of existing functionality:

Stop the test program on entry to the write() system call only when the file descriptor number is 7

I thought this one would be harder than the last, but now I'm not so sure, especially once you absorb some of the finer points from the last post.

Technorati Tag: MDB