Four Fours
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Every now and then I get addicted by a puzzle. Here's the first that I was ever addicted to. It was given to me my one of my maths teachers when I was a teenager. |
The goal is to just use four four's to represent all the integer numbers from 1 to 64. you can use whatever mathematical symbols you want to derive your answers. In the notation below, sqrt(x) is the square root of x and pow(x, y) is x to the power of y.
Over the years (and without the aid of a computer), I reduced the number of missing entries to 9.
Here's my solution. Digitized at last.
- (4 + 4) / (4 + 4)
- (4 / 4) + (4 / 4)
- 4 - sqrt(4) + (4 / 4)
- (4 * 4) / (sqrt(4) + sqrt(4))
- 4 + sqrt(4) - (4 / 4)
- 4 + sqrt(4) + sqrt(4) - sqrt(4)
- 4 + sqrt(4) + (4 / 4)
- 4 + 4 + 4 - 4
- 4 + 4 + (4 / 4)
- 4 + sqrt(4) + sqrt(4) + sqrt(4)
- (4! / sqrt(4)) - (4 / 4)
- (4 * 4) - sqrt(4) - sqrt(4)
- (4! / sqrt(4)) + (4 / 4)
- (4! / (4 - sqrt(4)) + sqrt(4)
- (4 * 4) - (4 / 4)
- sqrt(4) * sqrt(4) * sqrt(4) * sqrt(4)
- (4 * 4) + (4 / 4)
- (4 * 4) + 4 - sqrt(4)
- 4! - 4 - (4 / 4)
- 4 * sqrt(4! + (4 / 4))
- 4! + (4 / 4) - 4
- 4! - 4 + 4 - sqrt(4)
- 4! + (4 / 4) - sqrt(4)
- (4! * (4 / sqrt(4))) / sqrt(4)
- 4! + sqrt(4) - (4 / 4)
- 4! + 4 - sqrt(4)
- 4! + 4 - (4 / 4)
- 4! + sqrt(4) + (4 / sqrt(4))
- 4! + 4 + (4 / 4)
- 4! + sqrt(4) + sqrt(4) + sqrt(4)
- (pow(sqrt(sqrt(sqrt(4))), 4!) - sqrt(4)) / sqrt(4)
- (4 * 4) + (4 * 4)
- (pow(sqrt(sqrt(sqrt(4))), 4!) + sqrt(4)) / sqrt(4)
- 4! + 4 + 4 + sqrt(4)
- 4! + (4! - sqrt(4)) / sqrt(4)
- 4! + 4 + 4 + 4
- 4! + (4! + sqrt(4)) / sqrt(4)
- 4! + (4 * 4) - sqrt(4)
- no solution
- (4! * sqrt(4)) - 4 - 4
- sqrt(((4 + 4)! + 4!) / 4!)
- (4! * sqrt(4)) - 4 - sqrt(4)
- no solution
- (4! * sqrt(4)) - sqrt(4) - sqrt(4)
- no solution
- (4! * sqrt(4)) - 4 + sqrt(4)
- (4! * sqrt(4)) - (4 / 4)
- (4! * sqrt(4)) + 4 - 4
- (4! * sqrt(4)) + (4 / 4)
- (4! * sqrt(4)) + 4 - sqrt(4)
- no solution
- (4! * sqrt(4)) + sqrt(4) + sqrt(4)
- no solution
- (4! * sqrt(4)) + sqrt(4) + 4
- no solution
- (4! * sqrt(4)) + 4 + 4
- no solution
- pow(sqrt(sqrt(sqrt(4))), 4!) - 4 - sqrt(4)
- no solution
- pow(sqrt(sqrt(sqrt(4))), 4!) - sqrt(4) - sqrt(4)
- no solution
- pow(sqrt(sqrt(sqrt(4))), 4!) - (4 / sqrt(4))
- pow(sqrt(sqrt(sqrt(4))), 4!) - (4/4)
- 4*4*sqrt(4)*sqrt(4)
I see that Carl Johansen was addicted to this too, and even wrote a C++ program to solve it. He's gone to 100 and also used .4bar (.44444...), which wasn't something I incorporated.
It's nice to see the puzzle finally solved though.
( Dec 01 2006, 10:39:32 AM PST ) [Listen] Permalink Comments [6]
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Posted by Andrew Sayman on December 01, 2006 at 11:30 AM PST #
Posted by Rich Burridge's Blog on December 01, 2006 at 11:39 AM PST #
Posted by 63.107.91.99 on December 01, 2006 at 05:32 PM PST #
Posted by 69.86.230.147 on December 02, 2006 at 06:19 AM PST #
((4+4)-4)/4=1
(4*4)/(4+4)=2
((4+4)+4)/4=3
((4-4)*4)+4=4
((4*4)+4)/4=5
((4+4)/4)+4=6
(4-(4/4))+4=7
((4+4)+4)-4=8
((4/4)+4)+4=9
(44-4)/4=10
(4-(4/4))*4=12
(4*4)-(4/4)=15
((4+4)+4)+4=16
(4*4)+(4/4)=17
((4/4)+4)*4=20
((4*4)+4)+4=24
((4+4)*4)-4=28
Note that until 10 is not necessary to add 44 (or sqrt(4) or 4!).
Posted by Carlos GUSLiBu on December 02, 2006 at 07:55 PM PST #
Posted by Joachim on December 03, 2006 at 12:47 PM PST #